[osg-users] BoundingBox Problem

[Robert Osfield]

Hi Paul,

There is an osg::ComputeBoundVisitor that will compute the tight
bounding box of a subgraph, you can use this instead of the
node->getBound().

Robert.

On Jan 23, 2008 3:28 AM, Paul Pocock <Paul.Pocock at dsto.defence.gov.au> wrote:
> Hi,
> Wondering if anyone from the list can help me.
>
>  I have a 3x3 grid of tiles from a terrain database, my aim is to get an
> outline representation of this 3x3 by just using lines to represent each
> tile.
>
> My solution is the following:
>
> osg::BoundingBox bbox ;
> bbox.expandBy(node->getBound());
>
>
>
> vertices->push_back(bbox.corner(0));
> vertices->push_back(bbox.corner(1));
>
> vertices->push_back(bbox.corner(1));
> vertices->push_back(bbox.corner(3));
>
> vertices->push_back(bbox.corner(2));
> vertices->push_back(bbox.corner(3));
>
> vertices->push_back(bbox.corner(3));
> vertices->push_back(bbox.corner(2));
>
> vertices->push_back(bbox.corner(0));
> vertices->push_back(bbox.corner(2));
>
>
> My problem stems from the fact that the square is way to big. I believe
> it stems from the fact I'm using BoundingSphere to calculate extents.Is
> there an obvious solution to this problem - To get a square that is
> precisely the dimensions of the terrain tile?
>
> Thanks in Advance
>
> Paul
>
>
>
>
>
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